06:38PM | 03/18/05
Member Since: 04/10/03
116 lifetime posts
how do you figure the square footage of a house that is built in the shape of a half circle? thanks


07:54PM | 03/18/05
Member Since: 07/01/03
550 lifetime posts
Area of a circle = Pi x radius squared, or 3.14 times half the diameter squared.

In your case the radius is the distance from the long flat wall to the outer edge of the curved wall in feet.

so half a circle is [(3.14 x width) x (3.14 x width)]/2 or more simply (Pi*r^2)/2


02:24AM | 03/19/05
Member Since: 04/10/03
116 lifetime posts
thanks for your quick reply.


09:19PM | 05/24/07
Member Since: 05/24/07
1 lifetime posts
I'm trying to figure out how many yards of concrete I will need for my steps. They're half circle shape. The bottom step is has a radius of 15.7, and sticks out 5' foot from the house. The top step has a radius of 9.42, and sticks out 3' from the house. Both steps are 8" tall.


08:09AM | 05/25/07
Member Since: 03/08/06
192 lifetime posts
We may need a drawing of this. The part that sticks out away from the house, is this rectangle shaped? So it would be a half circle next to a rectangle?

check my math.


8/12*(9.42*2)*3 = 62.8ftcu

and 8/12*(15.7*2)*5 =104.7ftcu

plus your two semicircles

0.5 *(3.14159*9.42*9.42)*8/12= 258.1 ftcu


0.5 *(3.14159*15.7*15.7)*8/12= 92.9


I got 518 cubic ft.

There should be 9 cubict feet in a yard. so I get 57.6

Best to check the math. No warranty.


08:13AM | 05/25/07
Member Since: 03/08/06
192 lifetime posts
maybe there are 27cubic feet in a cubic yard. cr*p.

19.18. That sounds a little better


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