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I get 66.97725
Posted by rocket scientist on February 29th, 2004 03:27 PM
In reply to How do you measure sq.ft. in a room that's not square? by Mike on February 29th, 2004 12:13 PM [Go to top of thread]
The object would be to make the area into a square(s) or rectangle(s). Since you have a 3 ft opening to start with, that would be the short side of your first rectangle 3.0 by X (unknown distance to the 12 ft line) Then on either side of this rectangle you would have 2 right triangles, which if you flip one over and put it against the other would form another rectangle. Subtracting the 3 ft from the 12 ft gives you 9 ft or 4.5ft on either side to form the short sides of the 2 right triangles. Flip one triangle, put it against the other and you have a rectangle 4.5 by X (same as the other unknown)....join that to the first rectangle and you have 7.5 by X . Now you can either measure from the doorway to the 12ft line to find "X" or revert back to highschool trig to find "X" (8.9303") and multiply length X width Was this post helpful? Yes: or No:
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