Latest Discussions : Miscellaneous

djb

12:59PM | 10/31/03
Member Since: 10/30/03
1 lifetime posts
I want to put a 75 gallon aquarium on the 2nd floor of my home. It has a footprint of 48" x 18" and will weight approx. 525 lbs. Is there a formula to figure this?

Piffin

03:06PM | 11/02/03
Member Since: 11/06/02
1278 lifetime posts
Floors are normally designed for a "live load" of 40# per sq ft, but that is overall.

Your immediate area is going to have a load of a little more than twice that. Considering safety factors built in and the fact that the whole room will share the load, not being as highly loaded, youy should not have any trouble. If you are aware of which direction the floor joiusts run, it would be best to spread the weight over as many as possible and to place that load near the ends of the joists, rather than in the middle of the room.

Glenn Good

02:32AM | 11/04/03
Member Since: 09/10/03
314 lifetime posts
I would like to add one more thing...

The designed load for a bedroom or attic only has to be at 30#/sq. ft. instead of the 40# Piffin mentioned (which is the case for the other rooms). This does not necessarily mean yours are designed that way, but without knowing the span and size of the joists there is no way to tell. Keep the aquarium against a bearing wall and perpendicular to the joists and you should have no problems. (I have a 135 gallon aquarium in my house.)

Glenn www.consultationdirect.com

Wild Kard

08:37PM | 11/11/03
Member Since: 11/11/03
1 lifetime posts
I was trying to get answers to a similar problem i am having. My tank is a 120 gallon 4x2x2 and i estimate its total weight when functional to be around 1250 lbs. 30-40 lbs per square foot puts me way over in this case. If i layed down 2 by 12 and had the frame supported on multiple 2 by 12's would this make the difference i need? AM i stupid for even wanting it in my bedroom. Thanks for your time with this.


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